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Need help with algebra 2 rational equations

How would I solve problems like these?
27^2/3 (27 is the number and 2/3 is the exponent)
8^2/3

December 9, 2010

5 Comments • Newest first

wordk41

[quote=omransms]when you have a fraction in the exponent, the denominator is going to be your root.
So for example, if you had 27^(2/3), you'd take the cubic root of 27 then square the value.
So it would look like ( 3sqrt(27) )^2, remember, its not 3 times the square root of 27, its the 3rd root of 27, which in this case is 3, because 3x3x3= 27.[/quote]

How did you get the 3rd root of 27? Whats the 1st and 2nd root? Sorry I dunno much about it

Reply December 9, 2010
omransms

when you have a fraction in the exponent, the denominator is going to be your root.
So for example, if you had 27^(2/3), you'd take the cubic root of 27 then square the value.
So it would look like ( 3sqrt(27) )^2, remember, its not 3 times the square root of 27, its the 3rd root of 27, which in this case is 3, because 3x3x3= 27.

Reply December 9, 2010
simsands

@Omelet: Might need parantheses around 2/3. Depends on the calculator.

Edit, to solve this on your own;

As the exponent is divided by 3, you know that you'll want to find the cube root of 27. You have to know this. What number to the power of three equals 27? That would be 3. Now, as the exponent is 2/3, the answer will be 3^2, 9.

I hope that wasn't too confusing.

Reply December 9, 2010 - edited
wordk41

[quote=Omelet]I see no problem.

plug in on your calculator

27
^ 2
/ 3[/quote]

I have to learn to do it on my own. I forgot what my teacher said. Someone please help? D:

Reply December 9, 2010 - edited
Omelet

I see no problem.

plug in on your calculator

27
^ 2
/ 3

Reply December 9, 2010 - edited