Math help please
Hey,
can someone explain to me how to do this problem? I know for a fact that you do conjugates on this problem but i'm stuck somewhere in the process. So any help is appreciated. Thanks~
Problem: 2/(x-1) - 3/(x+2) = 1
Work: 2(x+2)/(x-1)(x+2) -3 (x-1)/(x-1)(x+2) - 1 = 0
2x+4/(x-1)(x+2) - 3x-3/(x-1)(x+2) - 1 =0
x+7/(x-1)(x+2) -1 = 0 <---- stuck at this point. do i conjugate the 1 also?
December 13, 2010
3 Comments • Newest first
oh ok. Thanks guys. =]
You just multiply everything by (x-1)(x+2). So you get -x+7=(x-1)(x+2). You can simplify that to x^2+2x-9=0, and then you use the quadratic formula to solve. -1+ or - the square root of 10.
... I think. xD;; Sorry, I'm not that great at math.
wouldnt it be -x+7/(x+1)(x+2) - 1 = 0