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really imporatant question help

How to calculate torque in rollers? please i need it detaild!

January 20, 2013

6 Comments • Newest first

LowWillpower

[quote=Watermelon]http://www.torqueleader.com/default/assets//Image/torque-calculation.gif

If you choose clockwise as your direction then your equation will be: M = F(a)*r1 + F(b)*r2
If you choose counterclockwise: M = -F(a)*r1 - F(b)*r2[/quote]
Just a note, counterclockwise is the standard, using the right hand rule. If it would make your hand curl so your thumb points out of the page, it's positive.

Reply January 20, 2013
Watermelon

http://www.torqueleader.com/default/assets//Image/torque-calculation.gif

If you choose clockwise as your direction then your equation will be: M = F(a)*r1 + F(b)*r2
If you choose counterclockwise: M = -F(a)*r1 - F(b)*r2

Reply January 20, 2013
Rondragon123

[quote=Watermelon]Do you have any examples or a question? I think it would be easier to explain with one.

T = Torque
F = Force that causes the torque
a = force's distance from the torque axis.

http://en.wikipedia.org/wiki/Torque[/quote]

so now that i know what these things means, what did u mean by choosing the direction? where does it fit in the equation?

Reply January 20, 2013
Watermelon

Do you have any examples or a question? I think it would be easier to explain with one.

T = Torque
F = Force that causes the torque
a = force's distance from the torque axis.

http://en.wikipedia.org/wiki/Torque

Reply January 20, 2013 - edited
Rondragon123

[quote=Watermelon]You just pick the direction and calculate the torque like you normally do.[/quote]

i dont know how to calculate torque. this mentor we have on our first robotic competition want me to search for him how to calculate the torque of polleys or rollers or w.e
im only at the 10th grade, how would i know what is this torque even means? i found on the internet this thing: T= F x a
tell me what does F and T and a means if you know.

Reply January 20, 2013 - edited
Watermelon

You just pick the direction and calculate the torque like you normally do.

Reply January 20, 2013 - edited