General

Oh man, logarithms...forgotten how to do it already.

[quote=tailedfox13]logx 3 = a
x^a = 3
x^(2a) = 9 ---> logx 9 = 2a

logx 25 = b
x^b = 25 = 5^2
x^(b/2) = 5 ---> logx 5 = b/2

then logx(9/5)
= logx 9 - logx 5
= 2a - b/2
= (4a-b)/2

I'm not sure I remember logarithms that well though. This might not be what you're looking for, but this is what I remember.[/quote]

Thanks, not sure if its right but I understood what you did.
L> Confirmation from someone