Need help in math. Exams are coming up
I am really stuck here o-o. Can anyone help me thankyou. Grade 10 math level.
Two acid solutions are to be mixed together.
• Solution A is 30% acid by volume.
• Solution B is 70% acid by volume.
How much of solution A is needed to mix with solution B to make an 800 mL mixture that is
54% acid by volume? Answer to the nearest millilitre.
edit: Wrong Section
can someone break this down for me i am really confused my level of math isnt that high.
January 27, 2013
9 Comments • Newest first
Maybe you need help in English as this is the wrong section.
Solution A: 0 mL
Solution B: 0 mL
Solution C: 800 mL
Solution C happens to be 54% acid by volume.
Guys, this isnt chemistry.... It's basic 8th grade algebra.
Do you just have to find the answers or do you have to use methods
[quote=MyTiramisu]Nvm what I said. Lemme read the question again.[/quote]
"How much of solution A is needed to mix with solution B to make an 800 mL mixture that is 54% acid by volume? Answer to the nearest millilitre."
It's stated that the total mL needed needed is 800 and that you need Solution A and Solution B to add up to it.
Nvm what I said. Lemme read the question again.
so confusing.
[url=http://www.enotes.com/math/q-and-a/how-much-solution-needed-mix-with-solution-b-make-340628]Google is your friend?[/url]
if it's in the wrong section just lock the thread and make a new one in the right section.