Im Stuck and Need Your Help
So ive been trying this problem for close to two hours and still can't come to a conclusion, and some help would be nice. So basil here we go :
btw....
^= the following number is an expontent
*= multiplication
2^2010 - 2^2009 - 2^2008 + 2^2007 = k * 2^2007
what is the value of K.
So mathletes give it your best shot and see if you can provide some support. Sorry for wasting your time, even if you just read the problem and thanks for all the help.
-Sincerely,
me
February 11, 2013
10 Comments • Newest first
Yea,, I'll just stick to my Financial math... Annuity, bond's and loans that are interrupted with varying interest rates are so much easier to do that whatever this is
[i]And i thought going to college for accounting was boring looking[/i] >.>
k= 2^2008
because 2^2010 is 2(2^2009) and 2^2009= 2(2^2008) etc...
@CreamyMilkV4
HA
isnt this like, sequences and series.
@Eaglesmash56:
well either:
do it by hand which would probably take a bit
find online calculator with no number cap if thats even possible
or I think there is a way to subtract exponents but I did that so long ago I don't remember exactly what to do.
[quote=iSeekMen]k= 2^2008?
EDIT: terrible explanation but 2^2010- 2^2009= 2^2009
2^2009-2^2008= 2^2008
@2^2008 + 2^2007 / 2^2007= k
the 2^2007's cancel out so you get 2^2008... unless im just bsing[/quote]
oh my god i think its gonna work out because i tried it on a lower level as in 2^4 - 2^3 and i got 8 which is equivalent to 2^3.
P.S. my girlfriend says she loves you because shes in the same class and she needed the answer too xD
k = 3 (I think)
2^2010 - 2^2009 - 2^2008 + 2^2007 = k * 2^2007
Split them up so they all have a common factor.
(2^3 * 2^2007) - (2^2 * 2^2007) - (2^1 * 2^2007) + (1 * 2^2007) = k * 2^2007
Factor out the 2^2007.
2^2007 * (2^3 - 2^2 - 2^1 + 1) = k * 2^2007
Divide 2^2007 out from both sides and combine the terms in the bracket.
8 - 4 - 2 + 1 = k
k = 3
[quote=Archfiendz]well to lazy to grab a clac but that seems REALLY easy. just multiply out the exponents subtract and add that last one. divide your answer by 2^2007 to get K.
As far as my Algebraic skills go that seems like the route to go...
EDIT: meant calc[/quote]
I tried that but the calculator i used provided by my schoo (Ti-84) gets an overload error because 2^2010 exceeds the number cap.
well to lazy to grab a clac but that seems REALLY easy. just multiply out the exponents subtract and add that last one. divide your answer by 2^2007 to get K.
As far as my Algebraic skills go that seems like the route to go...
EDIT: meant calc
Wrong section bud.