Algebra help please
On each day of its life a scroboscopus squares its number of legs. For example, if a scroboscopus has 2 legs on it first day of life, it would have 4 legs on its second day, and 16 legs on its third day. Tom bought some newborn scroboscopi. Some had 2 legs, some had 3 legs, and some had 5 legs. The total leg count was 58 legs. The next day the leg count was 164. The following day, the leg count was 1976. How many scroboscopi did Tom buy?
October 25, 2012
4 Comments • Newest first
i failed algebra
judge meEeEEeEEEe
[quote=play3r]2a + 3b + 5c = 58
4a + 9b + 25c = 164
16a + 27b + 125c = 1976
Solve?[/quote]
This.
Really not that bad.
the answer is 69
This is the most ridicious algebra based question I have seen in a while. e_e