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Alright, so my math teacher was looking up riddles and puzzles when he stumbled onto this one: 2=1
At first I didn't believe him till he wrote and all down, it actually make sense if you take it step by step. a = b Suppose a=1 and b=1 a+a = a+b Add 'a' to both sides 2a = a+b a+a=2a (1+1=2*a) 2a-2b = a+b-2b Subtract 2b from both sides 2(a-b) = a+b-2b 2a-2b = 2(a-b) 2(a-b) = a-b b-2b = -b (1-2=-1) 2 = 1 Divide both sides by a-b Now this statement is FALSE, I would have you post your comments about why YOU think it's wrong but you have the internet as a tool so what's the use? I will save you the time from looking it up and tell you why it's wrong. Notice the very last step: Divide both sides by a-b This is impossible when a and b are converted into numbers: Divide both sides by 1-1 You should know already that it is impossible to divide any number by 0. Since this is algebra it is correct and incorrect at the same time, just depends on your point of view I guess... Click here if you think this post is particularly interesting or helpful.
Poll - I have proof that 2=1
6%
10 votes This is cool!
28%
42 votes Lame
47%
70 votes I knew the answer! (Because I'm smart, I cheated, I saw this already, etc etc.)
17%
25 votes I'm confused...
Replies
I can prove 0 = 0 f3
z = a + bi 0 = -z + a + bi 0 = -a - bi + a + bi 0 = 0 This is the same as proving that 4x4=20.
New Pic: MapleMagical
GenuineLaughter: This is the same as proving that 4x4=20. Go on then... prove it... 2 =/= 1.
1 = 1
2 = 2 3 = 3 Don't be stupid. No matter what you do, these are numbers. you can't change it. New Blog: Just saw New Moon
• a = b Suppose a=1 and b=1
• a+a = a+b Add 'a' to both sides • 2a = a+b a+a=2a (1+1=2*a) • 2a-2b = a+b-2b Subtract 2b from both sides • 2(a-b) = a+b-2b 2a-2b = 2(a-b) • 2(a-b) = a-b b-2b = -b (1-2=-1) • 2 = 1 Divide both sides by a-b The second to last step does NOT imply the last step... New Pic: Crimsonwood Keep- The Attack
Step 6 is false.
• a = b Suppose a=1 and b=1
• a+a = a+b Add 'a' to both sides • 2a = a+b a+a=2a (1+1=2*a) • 2a-2b = a+b-2b Subtract 2b from both sides • 2(a-b) = a+b-2b 2a-2b = 2(a-b) • 2(a-b) = a-b b-2b = -b (1-2=-1) • 2 = 1 Divide both sides by a-b This would work if you wrote it correctly You are dividing by 0 which is the same as multiplying by 1/0 which is infinity So basically 2 x infinity = infinity Which is correct Rather than not dividing by zero, you can bypass stupidity simply by knowing that 2x0 and 1x0 are both zero.
NLNoFearNL: I can prove 0 = 0 f3 z = a + bi 0 = -z + a + bi 0 = -a - bi + a + bi 0 = 0 .... that thing was useless as hell... what you just did was: a = a 0 = -a + a 0 = 0 Why that z and 1+i thing? How do you cheat on a topic this easy?
no one is cheating
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My thoughts EXACTLY xD