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Thread starter
Nov 02 2009 +
LilAzn718
65 Scania Night Walker
 
Alright, so my math teacher was looking up riddles and puzzles when he stumbled onto this one: 2=1
At first I didn't believe him till he wrote and all down, it actually make sense if you take it step by step.
a = b Suppose a=1 and b=1
a+a = a+b Add 'a' to both sides
2a = a+b a+a=2a (1+1=2*a)
2a-2b = a+b-2b Subtract 2b from both sides
2(a-b) = a+b-2b 2a-2b = 2(a-b)
2(a-b) = a-b b-2b = -b (1-2=-1)
2 = 1 Divide both sides by a-b

Now this statement is FALSE, I would have you post your comments about why YOU think it's wrong but you have the internet as a tool so what's the use?
I will save you the time from looking it up and tell you why it's wrong.
Notice the very last step: Divide both sides by a-b
This is impossible when a and b are converted into numbers: Divide both sides by 1-1
You should know already that it is impossible to divide any number by 0.
Since this is algebra it is correct and incorrect at the same time, just depends on your point of view I guess...
Click here if you think this post is particularly interesting or helpful.
Poll - I have proof that 2=1
6%
10 votes   This is cool!
28%
42 votes   Lame
47%
70 votes   I knew the answer! (Because I'm smart, I cheated, I saw this already, etc etc.)
17%
25 votes   I'm confused...
Replies
11/04/09 +
iPl0x
55 KradiaEMS Crossbow
 
Satoshi1234: yay for being that 1% lol


My thoughts EXACTLY xD
11/04/09 +
NLNoFearNL
186 Scania Bishop
 
I can prove 0 = 0 f3

z = a + bi
0 = -z + a + bi
0 = -a - bi + a + bi
0 = 0
Nov 04* +
ryozukoLION
21 Bellocan Rogue
 
This is the same as proving that 4x4=20.
New Pic: MapleMagical
11/04/09 +
JamFlan
62 Bellocan Spearman
 
GenuineLaughter: This is the same as proving that 4x4=20.


Go on then... prove it...
11/04/09 +
Reeei
100 Khaini Ranger
 
2 =/= 1.
11/04/09 +
IceyJakeX
61 Scania I/L Wizard
 
1 = 1
2 = 2
3 = 3

Don't be stupid. No matter what you do, these are numbers. you can't change it.
Nov 04* +
Archerboy2k6
101 Windia Ranger
 
• a = b Suppose a=1 and b=1
• a+a = a+b Add 'a' to both sides
• 2a = a+b a+a=2a (1+1=2*a)
• 2a-2b = a+b-2b Subtract 2b from both sides
• 2(a-b) = a+b-2b 2a-2b = 2(a-b)
2(a-b) = a-b b-2b = -b (1-2=-1)
2 = 1 Divide both sides by a-b


The second to last step does NOT imply the last step...
online
11/04/09 +
MLiM
68 Broa Cleric
 
Step 6 is false.
11/04/09 +
JamFlan
62 Bellocan Spearman
 
• a = b Suppose a=1 and b=1
• a+a = a+b Add 'a' to both sides
• 2a = a+b a+a=2a (1+1=2*a)
• 2a-2b = a+b-2b Subtract 2b from both sides
• 2(a-b) = a+b-2b 2a-2b = 2(a-b)
• 2(a-b) = a-b b-2b = -b (1-2=-1)
• 2 = 1 Divide both sides by a-b

This would work if you wrote it correctly
You are dividing by 0 which is the same as multiplying by 1/0 which is infinity
So basically
2 x infinity = infinity
Which is correct
11/04/09 +
 
Rather than not dividing by zero, you can bypass stupidity simply by knowing that 2x0 and 1x0 are both zero.
11/05/09 +
TurneDnuorA
66 KradiaEMS Dawn Warrior
 
NLNoFearNL: I can prove 0 = 0 f3

z = a + bi
0 = -z + a + bi
0 = -a - bi + a + bi
0 = 0


.... that thing was useless as hell... what you just did was:

a = a
0 = -a + a
0 = 0

Why that z and 1+i thing?
11/05/09 +
Xcelic
72 Broa Crusader
 
How do you cheat on a topic this easy?
11/05/09 +
JamFlan
62 Bellocan Spearman
 
no one is cheating
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