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2/3 men and 3/5 women in town are married

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Gnawliryc Level 75 Windia Battle Mage 3
hey guys, i was wondering if anyone could do this problem since me, my dad, and some of my friends are arguing over the answer.

2/3 of the men in town are married. 3/5 of the women in town are married. What fraction of the men and women in town are not married?

my friends are saying the answer is 11/15 (which i think makes no sense), and my dad says the answer is 7/19. or is it something else? thanks in advance for helping.
Posted: April 2011 Permalink
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7/18 is what i got. I don't feel like explaining.

EDIT : Okay since i see people doing it weird. I see it as there are different populations of men to women in the town. Which only makes sense.

I made the numbers easier on me. So i said that there were 450 men in town that way 2/3 of them would make 300 men are married.
300 men married must mean there are 300 women married. So i now had to find the population of women.
(300/x) = (3/5)
3x = 1500
x = 500

So there are a total of 500 of women overall in town. An overall population of both men and women of 950.
Total not married = 950-600 = 350

350/950 = 7/19

Okay i messed up the first time but only because i did it quick in my head.
Apr 29 2011
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xVolcomStone Level 166 Windia Dark Knight
I got 1/2, then again I'm not that great at math.

those saying 11/15, over half of both men and women are married, so how can 11/15 people be unmarried?[/quote]

I think it has something to do with 2 different groups being involved in one answer.

I got 11/15 as well, and it makes more sense. I'm thinking I'm just gonna say 11/30 people, and don't ask me why.

EDIT: Oh, cool. I guessed the same answer as someone else, we must be right.
Apr 29 2011
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Ellinia Level 200 Bera Bishop
2/3 of the men in town are married. 3/5 of the women in town are married.

10/15 of men in town are married. 9/15 of women in town are married. That means 19/30 people are married, and 11/30 people are not married.
Apr 29 2011
2/3 of the men in town are married. 3/5 of the women in town are married.

10/15 of men in town are married. 9/15 of women in town are married. That means 19/30 people are married, and 11/30 people are not married.[/quote]

No, because there aren't the same number of men as there are women necessarily? It is 2/3 of x and 3/5 of y are married, meaning 1/3 of x and 2/5 of y aren't married; they don't go together
Apr 29 2011
okay, the answer is 11/30.
I got it different though.

5/15 men are not married
6/15 women are not married

average them out, 5.5/15 = 11/30.
Apr 29 2011
xVolcomStone Level 166 Windia Dark Knight
No, because there aren't the same number of men as there are women necessarily? It is 2/3 of x and 3/5 of y are married, meaning 1/3 of x and 2/5 of y aren't married; they don't go together[/quote]

Pretty sure it doesn't matter, since everything we're talking about here is ratios.
Apr 29 2011
11/30 people are unmarried

10/15 + 9/15 = 19/30
30 -19 = 11

... i think
Apr 29 2011
I would say it is 7/19. I'm going to go ahead and assume that the number of married men and women are equal since marriages generally involve 1 man and 1 woman. 2x/3=3y/5. By simplifying that, x=9y/10. For an example, I will say there is 10 women total, so there is 9 men. That's a total of 19 people. If 2/3 of the men are married, that is 6 men out of 9. Similarly, if there is 3/5 of the women married, that is 6 women out of 10. That makes 12 people married out of 19, and thus I say there is 7 people married out of 19.
Apr 29 2011
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