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Help with chem 11

hey guys i need help with some chemistry 11 homework if u can help that'd be great i missed one frikin class and missed a month's worth so its all about quantum numbers. how do i find quantum number for the outer shell electrons for N or Se? do i need a set of numbers?

also tried getting on maplestory and asked a bunch of people in henesys and 99% of them rich fancy players ingnored me or gave me attitude cuz most of them were like 10-14 year olds.......
thanks

December 6, 2013

8 Comments • Newest first

TightAss

[quote=Dorks]Quantum numbers follow a set pattern.
[url=http://chemed.chem.purdue.edu/genchem/topicreview/bp/ch6/graphics/6_23.gif]This was how I learned before I memorized where the shells were.[/url]

I think it goes
n = number of shells (s = 1, p =2)
l = n-1 (s = 0, p = 1)
ml = -l to +l (s : [ 0 ], p : [ -1 ][ 0 ][ +1 ]; brackets represent the magnetic numbers and the numbers are usually under the boxes)
ms = spin, it's either +1/2 or -1/2, any other number is wrong.

How you fill the orbitals is one arrow (e-) at a time and then fill the rest if there are any left.
N has 7 e- unless it's an ion or something idk but anyways it'd be
1s^2, 2s^2, 2p^3
1s: [l l]
2s: [l l]
2p: [l ] [l ] [l ]

=3=[/quote]

@DualKnightK

cool thanks for the help guys really appreciate it

Reply December 7, 2013
DualKnightK

It fills valence shells. Go from 1s2 2s2 2p6 3s2 and continue on from there. It also needs to meet the Pauli exclusion principle when you fill in arrows.
Your question on N (nitrogen) would be 1s2 2s2 2p3. Atomic number of N is 7 and 1s2 + 2s2 + 2p3 = 7.
For Se (selenium) you can use noble gas configurations and go back to Ar (Argon). So the configuration would be [Ar]4s2 3d10 4p4. Argon has 18 protons + 4s2 + 3d10 + 4p4 which equals 34, Se. This is probably really bad formatting but eh.

Reply December 6, 2013
Dorks

Quantum numbers follow a set pattern.
[url=http://chemed.chem.purdue.edu/genchem/topicreview/bp/ch6/graphics/6_23.gif]This was how I learned before I memorized where the shells were.[/url]

I think it goes
n = number of shells (s = 1, p =2)
l = n-1 (s = 0, p = 1)
ml = -l to +l (s : [ 0 ], p : [ -1 ][ 0 ][ +1 ]; brackets represent the magnetic numbers and the numbers are usually under the boxes)
ms = spin, it's either +1/2 or -1/2, any other number is wrong.

How you fill the orbitals is one arrow (e-) at a time and then fill the rest if there are any left.
N has 7 e- unless it's an ion or something idk but anyways it'd be
1s^2, 2s^2, 2p^3
1s: [l l]
2s: [l l]
2p: [l ] [l ] [l ]

=3=

Reply December 6, 2013 - edited
TightAss

[quote=NoobCake]I laughed, this kid asked hene hoes for help on his Chemistry homework[/quote]
like i told that girl up there i honestly didnt even expect real help i asked like 2 people at first then i just started wandering round to see how many people would actually respond they're all kinda arrogant

also, be on topic im dyin over here i should have taken a different science

Reply December 6, 2013 - edited
NoobCake

I laughed, this kid asked hene hoes for help on his Chemistry homework

Reply December 6, 2013 - edited
TightAss

[quote=Flexography]I love that you asked hene-hoes for help with your chemistry homework[/quote]

ya i honestly didnt even expect any of them to help but once in a while like one out of ten there are some mature older people hanging around. also just wanted to see for fun how ignorant those hene hoes were lol i was RIGHT
@xtripled thanks bro. chemistry is a real pain

Reply December 6, 2013 - edited
Swerve

never ask for help in henesys

Reply December 6, 2013 - edited
xtripled

[quote=Flexography]I love that you asked for help with your chemistry homework[/quote]

are you on your period or something? you seem more cranky than usual

OT: would love to help but it's been years since i've done chemistry

Reply December 6, 2013 - edited