General

The x-values will be irrational values.

If it was to give a rational value: you could sub x=1,2,3,6,-1,-2,-3,-6 and continue with the factor theorem.

Well by looking at sign changes, you know there's either 2 real positive or 2 complex and either case has a negative, so it would be best to use negatives. Using p/q like above said, you know its either +/-(1,2,3,6). Make sure you put in a 0 for the coefficient of x in your synthetic division.

[quote=Request]Use p/q and synthetic division
plus and minus The factors of 6 over the factors of 1

Try -3/2 or 3/2[/quote]

am i doing something wrong? they both didnt work (the -3/2 was really really close though...)

[quote=onigiri123]You might want to check to see if you're writing the question out right.

Edit: irrational numbers.[/quote]

i made sure

wait, what happened ot your legs o.o

[quote=2lazy2makeaname]How do you find the x-intercepts of this equation: x³ - 4x² + 6

i cant use a graphing calculator[/quote]

You might want to check to see if you're writing the question out right.

Edit: irrational numbers.

[quote=k151532]i forgot to mention, when i said possible, it means both + and - factors xD[/quote]

mind giving me hints? i tried x+6 , x+2, working on x+3 atm...

aren't you pretty smart? or did I mistaken you for someone else

Did something intercept your character's body?

[quote=k151532]the possible zeros of that equation can be found with this: possible factors of constant term (last number)/possible factors of first term coefficient

from there [b]trial and error[/b] with synthetic division[/quote]

QQ sigh...

you can set it to 0, but you will get an imaginary number.

you can't factor to find a real solution.

[quote=2lazy2makeaname]original problem was x³ -4x² + [b]6[/b]

not x³ -4x² + 6x[/quote]

Oh my bad, didn't see that

[quote=xorisa]By taking the x out, x(x²-4x+6)=0
Solve the quadratic.[/quote]

original problem was x³ -4x² + [b]6[/b]

not x³ -4x² + 6x

By taking the x out, x(x²-4x+6)=0
Solve the quadratic.

I don't think that's a parabola.

[quote=MistFTW]X-intercept is when y is 0. So set the equation equal to 0, and you get x³ - 4x² + 6 = 0.[/quote]

ok i tried that but

x³-4x² =-6
x²(x-4)=-6

this cant be right

[quote=Samla111]x³ - 4x² + 6 = 0
you can always try to factor it or use synthetic division[/quote]

how do you factor this? or how would you know what to divide it by?

x³ - 4x² + 6 = 0
you can always try to factor it or use synthetic division

X-intercept is when y is 0. So set the equation equal to 0, and you get x³ - 4x² + 6 = 0.

set it to 0 and solve for x