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Solve -3q^2 + 6q + 5 = 0 for q. If you get two solutions, separate them by commas, for example q = 1, 2.

Thanks

September 18, 2013

16 Comments • Newest first

monkey3842

[quote=crazypoorer]@monkey3842: You're assuming he first started learning. Logic[/quote]

I seriously don't get why you are still arguing with me lool.

[quote=opmeTK]don't know what state you live in, but until my AP Calc course, we were able to use calculators on tests and quizzes.[/quote]

Well most teachers don't allow graphing calculators on test and quizzes cause you can store information on there and some people use it to cheat.

Reply September 19, 2013
benjamin2708

The almighty Quadratic Formula.

x=[-b +or- (sqrt b^2-4ac)]/2a

Reply September 19, 2013
monkey3842

@crazypoorer: When did I assume? I suggested he may be 10 years old [b]or something[/b] loool i don't get why you are arguing with me. As I said, not everyone knows the quadratic formula when they first start learning.

Reply September 19, 2013
crazypoorer

[quote=monkey3842]Not really... for all we know he may be 10 years old or something. Everything is always hard when you are learning it for the first time.[/quote]

So you can assume he's 10 years old, but you can't assume he's 12 years old or higher? Makes sense.

Reply September 19, 2013
monkey3842

[quote=crazypoorer]You do know something's wrong when you don't know how to use the Quadratic formula[/quote]

Not really... for all we know he may be 10 years old or something. Everything is always hard when you are learning it for the first time.

Reply September 18, 2013
mujura1

-3q^2 + 6q + 5 = 0
As you can see in this equation, it can't be factored easily, so you must use the quadratic equation.
* remember to replace "x=" with your variable! (in this case it's a Q)
q = -6 +- sqrt ((6)^2 - 4 (-3) (5)) / 2 (-3)
q= - 6 +- sqrt (36 + 60) / -6
q = - 6 +- sqrt (96) / -6
If you are in 10th grade, then the answer would be:
q is a product of (-6 - sqrt(96) / -6, -6 + sqrt(96) / -6)
If you are in 11th grade you need to simplify the radical (96 in this case)
q = - 6 +- sqrt (16) sqrt (6) / -6
q = -6 +- 4 sqrt (6) / -6
q = 2 (-3 +- 2 sqrt (6)) / -6
q = -3 +- 2 sqrt (6) / -3
Then the answer would be:
q is a product of (-3 - 2 sqrt(6) / -3, -3 + 2 sqrt(6) / -3)

Reply September 18, 2013 - edited
crazypoorer

[quote=monkey3842]You do know right that most teachers don't allow graphing calculators on test.[/quote]

You do know something's wrong when you don't know how to use the Quadratic formula

Reply September 18, 2013 - edited
HolyDragon

http://www.wolframalpha.com/input/?i=-3q^2+%2B+6q+%2B+5%3D0

Reply September 18, 2013 - edited
checkmastyle

http://www.purplemath.com/modules/quadform.htm

have fun.

Reply September 18, 2013 - edited
monkey3842

[quote=crazypoorer]1) Spend $100 on a graphing calculator
2) Input the equation
3) Graph the equation
4) Find the zeroes
5) Now you know how to solve for zeroes[/quote]

You do know right that most teachers don't allow graphing calculators on test.

Reply September 18, 2013 - edited
crazypoorer

1) Spend $100 on a graphing calculator
2) Input the equation
3) Graph the equation
4) Find the zeroes
5) Now you know how to solve for zeroes

Reply September 18, 2013 - edited
Ecliptic

[quote=LowWillpower]You must have learned quadratic formula. If so, you should have already learned a few other ways to solve parabolas too. I don't know if anyone here is going to do your homework.[/quote]
The person below you apparently will.

Reply September 18, 2013 - edited
Karrie

quadratic formula
answer when + = -0.633
answer when - = 2.63
if you want the work just ask

@lowwillpower hello

Reply September 18, 2013 - edited
LowWillpower

You must have learned quadratic formula. If so, you should have already learned a few other ways to solve parabolas too. I don't know if anyone here is going to do your homework.

Reply September 18, 2013 - edited
Ecliptic

quadratic formula.

Reply September 18, 2013 - edited