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A ball is dropped from a ledge 20m high. At what height will the ball be at when it is moving 18m/s?

October 30, 2013

1 Comment • Newest first

darksuitguy

v*f = a(t)
t = 18 m/(9.8 m/s^2) = 1.8 s
sf = si + vi*t + (a/2)(t^2)
sf = 1/2 * (9.8 m/s^2) * (1.8 s)^2
sf = 16 m from where you dropped it or 4 m from the ground

Reply October 30, 2013 - edited