Chemistry Help - Percentage Yield
I was going through my chemistry review and I cannot figure out how to do this question so if anyone can help me out it would be greatly appreciated.
The follwing reaction is known to occur with a percentage of field of 82.7% at room temperature: Zn + S -> ZnS. If a chemist produced 826.77g of zinc sulfide at the end of an experiment, what mass of zinc was initially placed into the reaction chamber?
November 16, 2010
1 Comment • Newest first
Zn = 65g/mol
S = 32 g/mol
1 ZnS mol = 97 g
826.77g / 97 g = 8,52 mol
8,52 mol = 82,7%
X mol = 100%
x= 10,30 mol
1 mol Zn = 65 g
10,30 mol Zn = y
y = 669,64