Help with physics example problem
http://i61.tinypic.com/121a64l.png
I have a few questions about this problem:
1. Please explain clearly what the alpha symbol does in this problem. I know it means proportional to but what exactly does this do?
2. Why is a lambda added to the alpha in the exponents?
Or completely explaining what's happening would be extremely helpful too
August 20, 2015
3 Comments • Newest first
i hate science , nut i eo economics and business
I learned dimensional analysis a different way but from what I remember, the alpha, beta and lambda in your problem are just variables. You could have used a, b or c instead.
To answer your second question:
For dimensional analysis, you add the same dimensions' exponent (lambda and alpha in your case) together. So the first [L] and second [L] exponents are added together as shown in the third line of the solution. You can also see in that same line that the dimension [t] is raised to -2 lambda instead of keeping it in the denominator as seen in the second line.
Dimensional analysis can be very simple. I don't remember the specifics off the top of my head but I can message you later if you still need help. I hope what I commented ^ made some sense to you (assuming you know the basics of dimensional analysis).
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