General

2. I might be wrong but here goes.

(A+B)(AB)=34
(A^2)B +A(B^2) -34=0
Divide by B
(A^2) +A(B)-(34/B)=0

The question restricts them to positive whole numbers, meaning 34/B has to be a whole number.
That leaves B to either be 1, 2, 17, 34
If you go look at the cases, you can tell they won't be real or whole numbers.
B=1
A^2 +A -34=0
B=2
A^2 +2A -17=0
Etc
Doesn't look possible to me.

Now if its 90.
(A^2) +A(B)-(90/B)=0
To be part of the restriction, B has to be (1, 2,3,5,9,10,15, 18, 30,45,90)
You can tell you have all the cases with the line trick. (First point * last point = 90, Second point * Second last point = 90)
I didn't bother going through it all but I just set B=9

A^2 +A9 -10=0
(A+10)(A-9)=0
A=9

5. Find the height, take it in half. That's the base line to the center of the circle.
Now cut the base in half, that's the line of the base to the edge.
Pythagoras' Theorem for the line of the center to an edge of the circle, and that's your radius.

lol these are ez as poop

First one is 6