Help With Algebra 2- Restrictions
An example i have is a/bx-c=2/x-a, x =/= a, c/b. Solve for x
I was able to solve it correctly, but finding the restrictions was a problem i've been struggling with.
The /answerrestrictions to the problem is a =/= 0 , ab =/= c ---PLEASE show me how to get these by step.
All i know is that i set the denominate to 0, however, with this problem, i got something different. I must be missing something?
The problem also includes the restriction c/b, i don't know what that means? what do i do with these restrictions that are already included in the problem?
=/= ----not equal
September 16, 2014
2 Comments • Newest first
I asked someone ti hepp me with this and they said they set the final answer and replace x with a. From there they got ab =/= c. But I was wondering if I am suppose to do something with the restrictions in the original problem? (X =/= a and c/b
Assuming your question looks like this... a / (bx - c) = 2 / (x - a) for x & domain restrictions.
Cross multiply first... you'll end up with xa - a^2 = 2bx - 2c
Move variables around (subtract 2bx from both sides and add a^2 from both sides as well), you'll get this. xa - 2bx = a^2 - 2c
Factor out the x in the left-hand equation. x(a - 2b) = a^2 -2c
Divide by (a - 2b) from both sides and you'll end up with.... x = (a^2 - 2c) / (a - 2b)
To get the domain restrictions? if I'm reading correct, (a - 2b) =/= 0.
edit:
from what you've said, "The /answerrestrictions to the problem is a =/= 0 , ab =/= c ---PLEASE show me how to get these by step.". I'm not too sure why ab =/= c would matter in my case, but if a =/= 0... that would also imply that b =/= 0, because if........ "a" were to be 0, ( (0) - 2b) = 0, "b" would also have to be 0 in order to satisfy the equation to be zero for the denominator.
idk if this helps or not; I just don't fully understand what you're asking here.