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Just use Kirchhoff's Laws.

Sum of voltage drops in a loop is 0. Sum of currents into a node = sum of currents out of a node.

You should find they have the same current, which is also kinda obvious if you understand potentials. It wants to experience the least resistance, and since both have the same resistance, each will experience the same current and voltage drops.

First, combine the two 136 ohm resistors using resistors in parallel rules, then combine the equivalent resistor with the 52 ohm resistor using resistors in series rules. Calculate the current through the combination using Ohm's law I=V/R, then you can work backwards and break down the circuit back to its original components and solve for current through the 136 ohm resistors. (Par V, Seri-Q) Resistors in parallel have same potential, resistors in series have same charge (current)
Same thing I posted in your other thread.

Use nodal analysis and Ohm's Law