General

When in doubt I always just break it down into the voltage and current equations and solve the system.

Do it cooldude's way, or just calculate the equivalent circuit. First, combine the two 136 ohm resistors using resistors in parallel rules, then combine the equivalent resistor with the 52 ohm resistor using resistors in series rules. Calculate the current through the combination using Ohm's law I=V/R, then you can work backwards and break down the circuit back to its original components and solve for current through the 136 ohm resistors.

Step 1: Pick up your pencil/pen
Step 2: Act like you're going to attempt the question
Step 3: Throw pencil/pen, scrunch up questions & other related work & burn
Step 4: Cry

Okay so I got 0.5 Amps through each of 136 ohms

Process:
Step 1. Calculate R equivalent of the parallel 136 ohms resistors and then add it in series with 52 ohms resistor to get total current.
Step 2. Apply junction rule at the intersection after 52 ohms resistor. I1= I2 + I3 (where I2 is the 136 ohms resistor on left side an I3 is the right side)
Step 3. Apply junction rule to loop one (the loop with battery, left 136 resistor and 52 resistor) and figure out the current going into I2.
Step 4. Apply I2 back into junction rule and obtain I3.

Hope that helps

Edit: Mistake on step 3: It should loop rule not junction rule