Probability - Calculus help
Can someone help me with this question with probability? I don't know what to do.. thanks!
Q12. A card is selected from a pack of 52 playing cards, and NOT replaced. Then a second card chosen. Find the probability that:
a. both cards are hearts
b. both cards are aces
c. the first card is red and the second is black
d. both cards are picture cards
Thanks again
September 11, 2012
4 Comments • Newest first
opps my bad
but thank you @AmyrIin: and @LEGENDairy: !
Calculus? Where?
And yeah, Dairy Legend has posted the answers.
a. Pr(both cards are hearts) = 1/4 x 12/51
b. Pr(both cards are aces) = 1/13 x 3/51
c. Pr(the first card is red and the second is black) = 1/2 x 26/51
d. Pr(both cards are picture cards) = 3/13 x 11/51
Hopefully that's right...I don't think probability is part of calculus unless you're doing continuous random variables.
Oh crap. Is this the 52C2 crap again.
Jeez I hated this section so much. We did this toward the end of pre-calc and though I got it at the time, I totally forgot lol.
BUT EVERYTHING IS OVER 52C2 I CAN TELL YOU THAT MUCH And also, you're going to have to multiply some combinations in the numerator. I forget 8D
Okay, I thought about it in the shower:
for part b for instance, I think it might be 52C1 times 4C1 (choose 1 out of 52 and 1 out of the 4 aces) + 51C1 times 3C1 All over 52C2 which should yield 0.2722
I have no freaking idea and that number loooks actually ridiculously big. I'm going to sleep cause it's like 2 and if I got time I'll dig up some notes tomorrow if you still need help.
idk: http://hyperphysics.phy-astr.gsu.edu/hbase/math/probas.html