Quick Physics Homework Help Gr 11
A 1900kg car slows down from a speedof 25.0m/s to a speed of 15.0m/s in 6.25s. How much work was done on the car?
A 2600 kg truck travelling at 72 km/h slams on the brakes and skids to a stop. The frictional force from the road is 8200 N. Use the relationship between kinetic energy and mechanical energy to determine the distance it takes for the truck to stop.
I miss the whole lesson. PLease help me.
October 30, 2012
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I have one more question, didn't see this was assigned until now:
A bungee jumper has a mass of 73kg and falls a distance of 120 m before the bungee catches and sends the jumper upwards. Use the Law of Conservation of energy to calculate the speed of the jumper just before the bungee catches.
Thank you so much for any help
Hi don't mind if I jack a part of your thread.
A 0.495 kg wood block is firmly attached to a very light horizontal spring (k = 165 N/m) as shown in Fig. 6-40. It is noted that the block-spring system, when compressed 5.0 cm and released, stretches out 2.3 cm beyond the equilibrium position before stopping and turning back. What is the coefficient of kinetic friction between the block and the table?
:3
I can't find a way to turn the work of friction into force if there's no distance.
Thank you so much guys
Oh work, we're learning that tomorrow!
Fnet = mass*acceleration
a= distance / time
a= 10/6.25
a=1.6
Fnet=1900*1.6
Fnet=3040 and..... yeah dono what happens after that.