Quick physics help
In a series circuit plugged into the wall, 16.5Kj of work was done. How much charge passed through the circuit in 30s?
December 11, 2012
Quick physics help
In a series circuit plugged into the wall, 16.5Kj of work was done. How much charge passed through the circuit in 30s?
3 Comments • Newest first
inertia
W (joules) = 16.5Kj = 16.5 x 10^3 J
t (seconds) = 30
Q (coulombs) = ?
Find an equation that you can plug those into a formula.
What country are you from? Different countries use different levels of voltage: Europe/Asia = 220V, USA = 110V
Regardless though, you want to use the equation:
P = I*V
Where P is power (in joules, you'll have to convert), I is current (in amps) and V is the voltage (in volts).
Once you find out the current, just remember that amps are measured in coulombs per second (Q/s). *So just multiply the current by the total amount of time and that should give you the answer
*edit: Is the power you gave us the total power over 30 seconds? Or the power released by the circuit every second? (ie. the "work" done by the circuit) Without a time frame on the energy we can't really answer this problem