General

@Coourh @TheDarkHero3 yes, you guys are right. Sorry! (I never claimed to be smart.. but I do apologise for my incorrect advice.)

[quote=spectrumblue]@TheDarkHero3 If the quadratic has equal AND real roots, the discriminant should be greater than or equal to 0.[/quote]

The quadratic would have distinct roots if the discriminant exceeded 0...
What you're trying to say is if the question asked ONLY FOR REAL ROOTS. In that case, solve for when the discriminant is greater than or equal to 0.

TIL: people on basil are surprisingly bad at maths despite how smart they claim to be.

Do your own math homework u [insert profanity word] retard lol just go away from this world plzzzzzzzzzzzz

@TheDarkHero3 If the quadratic has equal AND real roots, the discriminant should be greater than or equal to 0.

[quote=qwertyalt]Find k if 2kx^2 + kx - (k - 1) = 0 has real and equal roots.

ty[/quote]

If the quadratic has equal roots and real roots, the discriminant must be equal 0. Set b^2-4ac equal to 0, and solve for k.
b^2-4ac=0
k^2-4*2k*(-(k-1))=0
k^2-8k*(-k+1)=0
k^2+8k^2-8k=0
9k^2-8k=0
k(9k-8)=0
k=0,8/9
k cant be zero or else original question is not a quadratic
therefore k=8/9