Help with weird probability question
A fair coin is to be tossed repeatedly. For integers r and s, not both zero,
let P(r, s) be the probability that a total of r heads are tossed before a total of
s tails are tossed so that P(0, 1) = 1 and P(1, 0) = 0.
Explain why, for r, s ≥ 1,
P(r, s) = (1/2) P(r - 1 , s) + (1/2) P(r, s - 1)
September 29, 2012
2 Comments • Newest first
[quote=kizox]Grade 12? o.o[/quote]
Yes.
Year 12, MX2
[quote=BroaCNTB]Fair coin = heads/tails 0.5/0.5?[/quote]
Yes, a fair coin is a coin that has exactly a 0.5 chance of landing on heads and 0.5 chance of landing on tails.