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Calc 3 Help Again

Hello guys. [url=https://40.media.tumblr.com/765b99db9b5ede033e85a2bee32ac49c/tumblr_nuurisee9i1ttnvtqo1_540.jpg]https://40.media.tumblr.com/765b99db9b5ede033e85a2bee32ac49c/tumblr_nuurisee9i1ttnvtqo1_540.jpg[/url]

Can someone please help me get started? I'm so lost right now.

September 18, 2015

4 Comments • Newest first

NonSonoFronz

Work = Force vector dot displacement vector = |Force| * |Displacement| * cos(theta) between the two vectors.
You are looking at the work done against gravity, so your force point straight down. You are at a constant 30 degree incline.

Reply September 18, 2015
HolyDragon

It's like Nam all over again man.

Reply September 18, 2015
zomgitbeandy

im getting war flash backs and i only had this class last semester

Reply September 18, 2015
HolyDragon

Work= F * D
Against gravity means going up or down.

You always start at A and end up at D as your final destination.

No matter what, you've only went a distance of 3sin(30) upwards.

Shouldn't 1 to 3 have the same answer if you are using the definition of work the walker has done?

Reply September 18, 2015