General

[quote=Symphs]http://oi61.tinypic.com/23hrpr4.jpg

Also, what do I even do with the Fnormal?

@Rationalism

Okay, if 120 is the initial height... I'll have:

y=1/2 (-9.81) t^2 + 7.72 + 120
y= -4.91 t^2 + 127.72
Will my step process be:
-127.72= -4.91 t^2
26.01= t^2
5.1= t

?[/quote]
Fnormal counters fg.

[quote=pascalio95]1) No clue what you're asking.

2) Yes, acceleration can be negative.

3) Break down velocity into components, and use kinematics formulas and the velocity in the y-direction to find time.

4) Tension would be inclined also, but tension is also a force, so it can also be broken into x and y components.

5) Period seems correct. Yes, frequency is 1/period.

Have fun! [/quote]

http://oi61.tinypic.com/23hrpr4.jpg

Also, what do I even do with the Fnormal?

@Rationalism

Okay, if 120 is the initial height... I'll have:

y=1/2 (-9.81) t^2 + 7.72 + 120
y= -4.91 t^2 + 127.72
Will my step process be:
-127.72= -4.91 t^2
26.01= t^2
5.1= t

?

[quote=Symphs]Even though it's moving on a surface?[/quote]

Sorry I should really say which one I'm talking about cause I have no idea what you're referring to. I was talking about the third diagram. the tension would be pointing northwest from the box.

Yea 120 is the initial height.

1) No clue what you're asking.

2) Yes, acceleration can be negative.

3) Break down velocity into components, and use kinematics formulas and the velocity in the y-direction to find time.

4) Tension would be inclined also, but tension is also a force, so it can also be broken into x and y components.

5) Period seems correct. Yes, frequency is 1/period.

Have fun!

[quote=Rationalism]Acceleration can be negative. I'll keep updating...

The tension is vertical because gravity is pulling it down.[/quote]

Even though it's moving on a surface?

*Edit* Wait what, initial height? Is that 120?

so.. y= 1/2 (-9.81) t^2 + (7.72(Viy)) + 120?

Acceleration can be negative. I'll keep updating...

The tension is vertical because gravity is pulling it down.

Plug the info into the projectile motion formula.

y = (1/2)at^2 + initial velocity + initial height

y = height

@Cherma
@mitarumetaro
@Avatar
@gatotsuwolf
@SoIntoYou

http://oi58.tinypic.com/2wn3b5u.jpg

First one is a bit hard to see. ''Can we still use elimination to get rid of tension, so I can isolate a, even though we're dealing with two different components?''

http://i.imgur.com/lyWwytV.jpg

What kind of questions?

^ lol =p

So.. what are your questions? o_0

Yes someone can

Yes, someone can