General

[quote=w00dywood]1) -28(W+2/3)^2+7(3w-1/3)^2
STEPS:

1. Factor out the GCF of -7 from each term in the polynomial
= -7(4(W+2/3)^2)-7(-(3w-1/3)^2)

2. Factor out the GCF of -7 from [-28(W+2/3)^2+7(3w-1/3)^2]
= -7(4(W+2/3)^2-(3w-1/3)^2)

3. The binomial can be factored using the difference of squares formula,
because both terms are prefect squares. The difference of squares formula
is: [a^2-b^2=(a-b)(a+b)]
= -7(2(W+2/3)-(3w-1/3))(2(W+2/3)+(3w-1/3))

4. Multiply 2 by each term inside the parentheses
= -7((2W+4/3)-(3w-1/3))(2(W+2/3)+(3w-1/3))

5. Multiply -1 by each term inside the parentheses
= -7((2W+4/3)+(-3w+1/3))(2(W+2/3)+(3w-1/3))

6. Remove the parentheses that are not needed from the expression
= -7(w2+4/3-3w+1/3)(2(W+2/3)+2w-1/3))

7. combine the numerators of all expressions that have common denominators
= -7(2W+4+1/3-3w)(2(W+2/3)+(3w-1/3))

8. Add 1 to 4 to get 5
= -7(2W+5/3-3w)(2(W+2/3)+(3w-1/3))

9. multiply 2 by each term inside the parentheses
= -7(2W+5/3-3w)((2W+4/3)+3w-1/3)

10. Combine the numeratos of all expressions that have common
denominators
= -7(2W+5/3-3w)(2w+4-1/3+3w)

11. Subtract 1 from 4 to get 3
= -7(2W+5/3-3w)(2W+3/3+3w)

12. Recude the expression [3/3] by removing a factor of 3 from the numerator
and denominator
= -7(2W+5/3-3w)(2W+1+3w)

FINAL Answer = [-7(2W+5/3-3w)(2W+1+3w)]

Finished answer for 1... use your knowledge now...[/quote]

Thanks

Expand the binomials, add them together, then factor. Use [url=http://www.purplemath.com/modules/factquad.htm]this[/url] as a reference if you don't know how to factor (you should be at this point if you're given questions like these)

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