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Algebra 2 Sequence help?

Okay I really don't understand these when it comes down to sequences.
There are like so many formulas and now I don't know which ones to use.
So you really don't need to give me the answer but like I don't know how to start/use which formulas to start.

[url=http://28.media.tumblr.com/tumblr_m39845aQPn1qf4pfwo1_500.jpg]Finest of the uploads.[/url]

The link is weird so just copy and paste it again starting from 28.

April 29, 2012

5 Comments • Newest first

Xgo321

[quote=Momo123]This is algebra 2.... i'm learning this in pre calc and this is my last section lol[/quote]

Well Algebra 2/Trigonometry is my 3rd year math course for high school and I took Algebra 1 in the 8th grade so yeah. I have no clue why they call it Algebra 2 when it's like Algebra 3 if you follow the way the school goes LOL

Aw I have to take Pre-Cal next year for my placement into AP Calc </3 Long process.

Reply April 29, 2012
Momo123

This is algebra 2.... i'm learning this in pre calc and this is my last section lol

Reply April 29, 2012
Xgo321

[quote=TheTuvvo]1. If I'm correct, you shouldn't have to use any formulas for this one. Just plug in 1, 2, 3, 4, and 5 for n in the given formula.

First 5 terms: 2, -2, -6, -10, -14

It is arithmetic because you can see that it is decreasing by 4 each term (the common difference, d).

2. Once again, just plug in the first 5 terms.
a)
First 5 terms: 3/2, 1/2, -1/2, -3/2, -5/2
Then graph them as (n,an) Ex. (1,3/2) (2,1/2)
b)
You should get a straight line, with the slope -1, I think.
c)
To find the common difference, d, use the formula an=a1+(n-1)d

1/2=3/2+(2-1)d
-1=(1)d
-1=d

3. The sequence is an arithmetic progression. First you need to find the 35th term by using the formula an=a1+(n-1)d:

a35=7+(35-1)2
a35=75

Then use the sum formula Sn=n/2(a1+an)

S35=(35/2)(7+75)
S35=1432

4. The sequence is also an arithmetic progression.

Use the formula an=a1+(n-1)d, solving for an.

an=30+(n-1)-4
an=30-4n+4
an=34-4n

Plug it into the formula Sn=n/2(a1+an) and solve for n.

-210=(n/2)(30+34-4n)
-210=(n/2)(64-4n)
-210=32n-2n^2
-105=16n-n^2
n^2-16n-105=0
(n-21)(n+5)=0
n= 21, -5

n MUST be a positive number so [b]n=21[/b][/quote]

Oh my! Thanks so much!

(I actually forgot that n was actually the term number so I was confused from there, oops.)

And I kind of did each question myself and if I was stuck, I checked it and saw what I did wrong.

Thanks so much! <3

Reply April 29, 2012
Xgo321

[quote=Watermelon]Does all American math books have a space for you to answer below the question? Like don't you have to do it on a notebook or something?[/quote]

Haha, I guess it's easier for the teacher to check it and for the students to do.

Reply April 29, 2012
Watermelon

Does all American math books have a space for you to answer below the question? Like don't you have to do it on a notebook or something?

Reply April 29, 2012