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General Tech

How do you make Maplestory Music Videos Requirements? Title's bit vague. I have been recently browsing through various MMVs, and I became interesting in making an MMV. If I do start, I don't expect it to be professional, but one thing I would like to know is what are the best methods and programs involved in good MMVs? (I understand that there are different styles people use) Summary: 1) What programs will I most likely be using? (I have Vegas and Photoshop already) 2) How do I manipulate movements of sprites (separate movement from body and head, eg. tilting head, hair, etc.) 3) How do I (and where do I get) create special effects and transitions? I know all these seem already a lot, but if anyone is willing to even guide me a little, that

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Help with Chem Lab Molar Volume Type of experiment: determine the molar volume of H2 at STP. This is based on "collected over water". You are given a piece of Mg ribbon. You steel wool it, then weigh it. You get a small-holed rubber stopper. Using a copper wire, you tie the ribbon and the stopper together. You have a long thin test tube filled with excess HCl (so Mg is limiting) and fill the rest of the volume with filtered water. You then plug the stopper into the test tube (the reactants won't react because HCl is dense, it being on the bottom). You also have a graduated cylinder filled with tap water prepared beforehand. You flip the whole test tube upside down and quickly put it inside the cylinder. The HCl will fall to meet t

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Very Hard Polynomial Questions It's not the very very basic things you learn with polynomials. A little harder. 1. Find all zeros of f(x)=128x^3-48x^2+1 given that one linear factor occurs twice. 2. Find all zeros of f(x)=x^4-54x^2+216x-243 3. Find the relationship between p and q such that the zeros of the polynomial x^2+px+q are in the ratio 3:2 4. Find the value of m =/= 0 if one of the zeros of x^2+(m+1) is three times the other. 5. Find the values of p if the polynomial x^2+px+2 a. has 2 as one of its zeros; b. has zeros whose sum is twice their product; c. has zeros whose squares have a sum of 21; d. has zeros whose difference is 3/2. 6. Use the remainder theorem to show that x+a+b+c is a factor of the polynomial f(x) = (x+a)(x+b)(x+c

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Very Hard Polynomial Questions It's not the very very basic things you learn with polynomials. A little harder. 1. Find all zeros of f(x)=128x^3-48x^2+1 given that one linear factor occurs twice. 2. Find all zeros of f(x)=x^4-54x^2+216x-243 3. Find the relationship between p and q such that the zeros of the polynomial x^2+px+q are in the ratio 3:2 4. Find the value of m =/= 0 if one of the zeros of x^2+(m+1) is three times the other. 5. Find the values of p if the polynomial x^2+px+2 a. has 2 as one of its zeros; b. has zeros whose sum is twice their product; c. has zeros whose squares have a sum of 21; d. has zeros whose difference is 3/2. 6. Use the remainder theorem to show that x+a+b+c is a factor of the polynomial f(x) = (x+a)(x+b)(x+c

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Another Hard Trig Set 1. If tan^2(alpha)-2tan^2(beta)=1, prove cosine2alpha+sin^2(beta)=0 2. If t=tan(1/2*theta), express the square root of --->>>>>>>>>>>>(1+sin(theta))(3sin(theta)+4cosine(theta) +5) in terms of t 3. If sin(3theta)=p and sin^2(theta)=(3/4)-q, prove that p^2+16q^3=12q^2 4. Prove 2cot(1/2)A+tanA=tanAcot^2(1/2)A 5. If 2cosine(3theta)=x+(1/x), show that 2cosine(3theta)=x^3+(1/x)^3 6. If secA-tanA=x, prove then tan(1/2*A)=(1-x)/(1+x) I forgot why I wrote the following, but I think I wrote these down as hints: >>>sin3(theta)=3sin(theta)-4sin^3(theta) >>>cosine3(theta)=4cosine^3(theta)-3cosine(theta) Btw sorry I couldn't make it neater. And I had to spell out "cosine&quo

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Help With Trigonometry 1. If sec(theta)-cos(theta) = a and cosec(theta)-sin(theta)=b, prove that a^2b^2(a^2+b^2+3)=1 2. Prove that cos(theta)-1 + cos(theta)+1 = sec(theta) + tan(theta) >>>>>>>>>--------------------------------------- >>>>>>>>>sec(theta) + tan(theta) 3. Find the general solution to tan(x)tan(4x)=1 4. Find the general solution to tan(3theta)=cot(2theta) 5. Find the general solution to the equation [2 tan (x-1)]^2 = 3[sec^2 (x-2)] Any help is appreciated and thanks in advanced ^^ EDIT: Shoot, I wrote number 2 wrong. it should be [cos(theta)-1]/[sec(theta)+tan(theta)] + [cos(theta)+1]/[sec(theta)-tan(theta)] = sec(theta) + tan(theta)

General Fun

Youve been infected by a virus Instructions: a) Say 2 active members' names (to infect). They will later be officially listed on the infected list. b) Say 1 active members' name (to cure). They must be infected (on the list) in the first place. Rules: 1) A infected member may not be infected. If a user accidentally "infects" the infected, it will not be counted. 2) A cured member may not be cured. It will also not be counted. 3) To infect someone, choose anyone not on the infected list. 4) To cure someone, choose someone on the infected list with an "X" beside their name. 5) Cured people may not infect or cure others. 6) By posting here, you are infected. So if you are cured, take that as a temporary "ban". 7)

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