2/3 men and 3/5 women in town are married
hey guys, i was wondering if anyone could do this problem since me, my dad, and some of my friends are arguing over the answer.
2/3 of the men in town are married. 3/5 of the women in town are married. What fraction of the men and women in town are not married?
my friends are saying the answer is 11/15 (which i think makes no sense), and my dad says the answer is 7/19. or is it something else? thanks in advance for helping.
April 29, 2011
16 Comments • Newest first
Are same sex marriages put into the equation?
[quote=Ryzanz]Pretty sure it's 2/5 lols.
2/3 x 3/5 = 6/15 = 2/5[/quote]
... what? sorry, i just dont understand the logic behind your work here O_O
thanks everyone for your responses! im going to go with 7/19, as that seems to be the most plausible answer in this situation. for those who got different answers, thank you for taking time out of your busy lives to attempt this problem.
[quote=xMyRice]7/18 is what i got. I don't feel like explaining.
EDIT : Okay since i see people doing it weird. I see it as there are different populations of men to women in the town. Which only makes sense.
I made the numbers easier on me. So i said that there were 450 men in town that way 2/3 of them would make 300 men are married.
300 men married must mean there are 300 women married. So i now had to find the population of women.
(300/x) = (3/5)
3x = 1500
x = 500
So there are a total of 500 of women overall in town. An overall population of both men and women of 950.
Total not married = 950-600 = 350
350/950 = 7/19
Okay i messed up the first time but only because i did it quick in my head.[/quote]
This.
this question is actually impossibe since we dont know if the men are married to women out of town or vise versa (also not all marriges are between man and woman)
[quote=PukeADot]No, because there aren't the same number of men as there are women necessarily? It is 2/3 of x and 3/5 of y are married, meaning 1/3 of x and 2/5 of y aren't married; they don't go together[/quote]
Pretty sure it doesn't matter, since everything we're talking about here is ratios.
2/3 of the men in town are married. 3/5 of the women in town are married.
10/15 of men in town are married. 9/15 of women in town are married. That means 19/30 people are married, and 11/30 people are not married.
[quote=Caelestys]I got 1/2, then again I'm not that great at math.
those saying 11/15, over half of both men and women are married, so how can 11/15 people be unmarried?[/quote]
I think it has something to do with 2 different groups being involved in one answer.
I got 11/15 as well, and it makes more sense. I'm thinking I'm just gonna say 11/30 people, and don't ask me why.
EDIT: Oh, cool. I guessed the same answer as someone else, we must be right.
arg, i hate these types oh questions
i really hope someone solves this because i always forget these questions after my teachers teach me
[quote=Caelestys]I got 1/2, then again I'm not that great at math.
those saying 11/15, over half of both men and women are married, so how can 11/15 people be unmarried?[/quote]
Im not so sure.... MATH HAS FAILED US ONCE AGAIN
2/3 can be rewritten as 10/15 and 3/5 can be rewritten as 9/15 u do the rest
1/3 + 2/5 = 11/15
Simple math?
The scenario can play out differently. One way is to assume they're married to each other. In that case, the town in simplest form has 9 men and 10 women, with 19 people total. 2/3 of 9 is 6, and 3/5 of 10 is 6, so 6/19 people are married.
If they're all married to different people from out of town, 2/3 is 2 people and 3/5 is 3 people so 5/8 of the people are married.
(2/3) = 10/15 total men married
(3/5) = 9/15 total women married
Assuming # of men = # of women, you've got 19/30 married, leaving 11/30 not married.
If this is horribly wrong, don't flame. It's late. ._.
11/15? maybe I dunno I just did it randomly in 2 seconds
The real question is:
[i]Who are they married to?[/i]