General

@sparkshooter:
i was thinking about using sin, but then id have to find the cosine of 6/5

[quote=BrandonIsBack]I thought that only worked for right triangles.[/quote]
No, it works for every (real) triangle.

[quote=ianzbored]@Castrius: yeah i know that but i just dont know how to use them[/quote]
To my knowledge, there's no other possible way to solve for the angle without a right angle or trigonometry functions.

@Castrius: yeah i know that but i just dont know how to use them

[quote=ianzbored]thanks guys, its just that i didnt learn cosine yet, just tan cos, and sin and it didnt work[/quote]

tan=Tangent
Cos=Cosine
sin=Sine
Csc=Cosecant
Cot=Cotangent
Sec=Secant

LOOOOOOL. omfg. I was about to post this: "iirc Wasn't there like a rule where the two smallest sides of a triangle added together must be greater than the largest side of the triangle? so 16 + 20 = 36. so, the triangle side cannot be 37? and then you solve for the angle? I actually, like the ones above me, don't understand what you're asking. Are you just asking to find the angles? o-o" and your problem was something so simple. ahahahahaha.
Yeah, well learn to convey stuff better. as well as your maths, man. x.x

[quote=ianzbored]thanks guys, its just that i didnt learn cosine yet, just tan cos, and sin and it didnt work[/quote]

lol what

thanks guys, its just that i didnt learn cosine yet, just tan cos, and sin and it didnt work

[quote=sparkshooter]Just use the Law of Cosine.
(c)^2 = (a)^2 + (b)^2 - 2(a)(b)cos(C)
C is the angle opposite to side c.
Plug it in and you can find each angle measure.[/quote]

I thought that only worked for right triangles.

Acute is less than 90 degrees, Right angle is exactly 90 degrees and Obtuse is more than 90 degrees.
I'm having trouble understanding what you're trying to ask though but I hope the above helps.

Just use the Law of Cosine.
(c)^2 = (a)^2 + (b)^2 - 2(a)(b)cos(C)
C is the angle opposite to side c.
Plug it in and you can find each angle measure.