Rearranging a Physics Formula
Hey Basil, this might be a stupid question but I just need a little bit of help on rearranging this formula to solve for g. I'm not exactly sure if what I have is right because I'm not 100% sure when exponents and square roots are involved.
The equation is
T = 2pi sqrt(L/g)
Would I square everything and then multiply both sides by g and then divide both sides by T squared?
EDIT: I'm not a bad student... I'm just asking for clarification. I average high 90s ):
September 17, 2013
7 Comments • Newest first
[quote=GAubertin]That's what everybody says: "My teacher is bad."
But there is no harm in asking so I don't see why you can't.[/quote]
Yeah, everyone says that, but trust me when I say my teacher is actually bad. The other teachers in the physics department understand too that he can't teach very well, even though he's really intelligent.
And exactly. Don't know why I went to Basil though.
[quote=momozzz]She has a point. You always learn the steps to it before you actually apply the formulas so he's been slacking.[/quote]
No, my teachers crazy. He barely teaches us anything. He just tells us to do it.
I don't see any harm in asking for clarification... and I'm pretty sure I had the correct answer anyhow.
[quote=prestigechef]Most useless comment ever.
Excluding this one. [/quote]
She has a point. You always learn the steps to it before you actually apply the formulas so he's been slacking.
[quote=fun2killu]this is like basic algebra skills. I feel bad that you don't know this yet
airforce1 has given the correct solution[/quote]
I just said I wasn't 100% sure and didn't wanna mess up my lab because of it. Just needed clarification.
g = [4pi^2(L)]/[T^2] works too, right?
[quote=fun2killu]this is like basic algebra skills. I feel bad that you don't know this yet
airforce1 has given the correct solution[/quote]
Most useless comment ever.
Excluding this one.
this is like basic algebra skills. I feel bad that you don't know this yet
airforce1 has given the correct solution
T/2pi = sqrt(L/g)
(T/2pi)^2=L/g
g = L/[(T/2pi)^2]