General

[quote=HolyDragon]About the bisector, AFAIR, it means the angle between the black line and AB (zeta) and y-1 has to be the same. The 2x -13 includes the y-1 inside and is why I calculated for Zeta. Did I forget something?[/quote]

Oh, oops, misread the question. Yeah, I thought angle 2x - 13 was for EAB, not EAD. In that case, y - 1 == 0.5(2x-13) if AB is a bisector. So you're right. Sorry!

[quote=spitfirebal2]Went to Mission San Jose High School in your school district, let's see, this shouldn't be anything new...

Huh, I'm getting 34.8 for y, and... 0 for x. After checking my work, too. The only theorems that I applied were 3 angles add up to 180 and supplementary angles add up to 180.

But then the bottom right angle has a degree of -6. Wat.

It checks out mathematically, though.

Edit: To check if AB is a bisector, just check if 2x - 13 =? y - 1. If they're equal, it's a bisector. Not sure what 2nd comment was talking about with another variable zeta; his advice would suggest that it's a bisector if 2x - 13 = 0, which is false.

Edit2: Looking at the other problems on the sheet, I got curious and finished the worksheet. Now considering brushing up on my geometry skills with other worksheets. Not sure if result is good.[/quote]

About the bisector, AFAIR, it means the angle between the black line and AB (zeta) and y-1 has to be the same. The 2x -13 includes the y-1 inside and is why I calculated for Zeta. Did I forget something?

[quote=superswift12]Really Mission San Jose ? How did you survive Lol ? I go to Irvington. Could you give me the other answers for the sake of my curiosity thanks ?[/quote]

I was pretty relaxed in school. A lot of people in Mission are pretty crazy but I only took around 3 APs per school year, so I wasn't that busy.

I didn't bother doing 1 because proofs are annoying in my personal opinion.

2a. (1, -1). Midpoint formula.
2b. Slope of AB is -2/3, and the perpendicular bisector is a line passing through the midpoint with the slope inverse of AB (3/2). So any point on the line y + 1 = 3/2(x - 1) should do.
2c. It's not a right triangle. You can kind of plot the points on a grid and check the slopes of the lines that make up the triangle. If two of the lines are perpendicular, so if their slopes are inverses of each other, you have a right triangle. That's not the case here, though.

3 is another proof...

4 is a graphing thing but should be fairly straightforward. The area of the triangle is 15.5, probably.

5a. is solved(?)
5b. If the x and y values for part a were right (kind of weird how the triangle has a negative degree angle despite being mathematically valid but whatever) ABC is not a right triangle because angle BAC isn't a right angle, angle BCA isn't a right angle, and 180 - BCA - BAC isn't a right angle either.

6 QR has a length of 16.8. This one is basic algebra, but you do have to know that congruent angles implies congruent sides.

7 Assuming Digger the dog can't dig, a. roughly 26 feet and b. the entire yard, 35 feet.

I'm not really 100% sure of my answers since I did these quickly.

[quote=spitfirebal2]Went to Mission San Jose High School in your school district, let's see, this shouldn't be anything new...

Huh, I'm getting 34.8 for y, and... 0 for x. After checking my work, too. The only theorems that I applied were 3 angles add up to 180 and supplementary angles add up to 180.

But then the bottom right angle has a degree of -6. Wat.

It checks out mathematically, though.

Edit: To check if AB is a bisector, just check if 2x - 13 =? y - 1. If they're equal, it's a bisector. Not sure what 2nd comment was talking about with another variable zeta; his advice would suggest that it's a bisector if 2x - 13 = 0, which is false.

Edit2: Looking at the other problems on the sheet, I got curious and finished the worksheet. Now considering brushing up on my geometry skills with other worksheets. Not sure if result is good.[/quote]
Really Mission San Jose ? How did you survive Lol ? I go to Irvington. Could you give me the other answers for the sake of my curiosity thanks ?

Went to Mission San Jose High School in your school district, let's see, this shouldn't be anything new...

Huh, I'm getting 34.8 for y, and... 0 for x. After checking my work, too. The only theorems that I applied were 3 angles add up to 180 and supplementary angles add up to 180.

But then the bottom right angle has a degree of -6. Wat.

It checks out mathematically, though.

Edit: To check if AB is a bisector, just check if 2x - 13 =? y - 1. If they're equal, it's a bisector. Not sure what 2nd comment was talking about with another variable zeta; his advice would suggest that it's a bisector if 2x - 13 = 0, which is false.

Edit2: Looking at the other problems on the sheet, I got curious and finished the worksheet. Now considering brushing up on my geometry skills with other worksheets. Not sure if result is good.

2nd one is right and wrong, my teacher is looking for x,y values in primary importance.

i dont know this and im in calculus

Here's my guess from a quick look.

<ABD = Alpha

<DBC = Beta

4y+6+ x+y = 180

y-1 +4y+6 + Alpha = 180

x+y 2x-6 + Beta = 180

Alpha + Beta + y-1 + 2x-6 = 180

Then solve for x and y.

Bisector

2x -13 -( y-1) = Zeta

Zeta has to equal y-1 to be bisector.

[url=http://ihs-fusd-ca.schoolloop.com/file/1408076734706/1327737725561/2590471180330481294.pdf?filename=GHPTCh4.pdf]Feeling lazy but I'll fix the link for you.[/url]